Sven's Official BrainTeaser Thread !! and Sander.

[TW89]

i think the come and lost one is stars (with the exception of the sun)

Correct
Someone elses turn now lol

[Sander]

okay it's time for my riddles again  :thumbsup:

there's a baker in his shop. he's about to close the door since it's almost 17:00, but then 3 men come in. the first man buys half of the pies the baker has left + another half pie. the 2nd and the 3rd man do the same and now the baker has exactly 0 pies left. he's also happy since he didn't have to cut a pie in two halfs. the question: how many pies did the baker have before the 3 men came to buy them?

[sputnik]

14 pies?

[a;sdlfkjas;df]

7?

[Royal Freakiness]

1 pie???  :dontknow:
I have no idea how you guys try to come up with an answer....

[a;sdlfkjas;df]

I have no idea how you guys try to come up with an answer....

i looked at it this way (if i'm looking at it correctly):

you can't have an even number of pies.  e.g. 12.  12/2=6-.5=it will always be x(where x is an odd integer)/2 after the first uyer.  which when divided by 2 again will give you the (same x)/4 - (2/4).  so, there will still be an odd integer in the numerator/4.  that would mean that the baker would have to cut the pie into two halves (1/4s).  then, if my answer is correct, i just did a simple process of elimination.

[sputnik]

i looked at it this way

working backwards
0+1x2=2
2+1x2=6
6+1x2=14

going forwars

14 pies. man one buys half (7) and another (6). man two buys half (3) and another (2). man one buys half (1) and another (0)

[a;sdlfkjas;df]

+ another half pie

i read this as .5 pies

[Macca]

i looked at it this way

working backwards
0+1x2=2
2+1x2=6
6+1x2=14

going forwars

14 pies. man one buys half (7) and another (6). man two buys half (3) and another (2). man one buys half (1) and another (0)

7+6+3+2+1 = 19, not 14...

also he said + another half pie =S i interpreted it like this

letting t=total
t = first guy + second guy + third guy
first guy = t/2 + 0.5
second guy = (first guy - 1)/2
third guy = (second guy - 1)/2
letting x = first guy
t = x + (x-1)/2 + (((x-1)/2)-1)/2
2t = 2x + (x-1) + ((x-1)/2)-1
2t + 1 = 2x + (x-1) + (x-1)/2
4t + 2 = 4x + 2x - 2 + x - 1
4t + 5 = 7x
x = 4t/7 + 5/7
so the first guy bought that much in comparison to the total
t/2 + 0.5 = 4t/7 + 5/7
7t/2 + 3.5 = 4t + 5
7t + 7 = 8t + 10
7t = 8t + 3
t = |-3|
=3

therefore he had 3 pies in total... the first guy bought half this amount (1.5) + another 0.5 (so he bought 2)... the next guy bought half of this (0.5) and bought another 0.5 (so he bought 1)... now theres 0 remaining pies for the third guy... who bought 0/2 = 0

 :dontknow:

[a;sdlfkjas;df]

7+6+3+2+1 = 19, not 14...

those are his number of pies left at that current time

now theres 0 remaining pies for the third guy... who bought 0/2 = 0

the last person also takes .5?

[Macca]

7+6+3+2+1 = 19, not 14...

those are his number of pies left at that current time

now theres 0 remaining pies for the third guy... who bought 0/2 = 0

the last person also takes .5?

shh u werent meant to notice that part...

 :bang:

[a;sdlfkjas;df]

 :lol: