No one did beg to differ. Hold on folks, here come the solution:
The different sums:
2=1+1
3=2+1
4=3+1=2+2
5=4+1=3+2
6=5+1=4+2=3+3
7=6+1=5+2=4+3
8=7+1=6+2=5+3=4+4
9=8+1=7+2=6+3=5+4
10=9+1=8+2=7+3=6+4=5+5
11=10+1=9+2=8+3=7+4=6+5
The correspondning products:
1
2
3, 4
4, 6
5, 8, 9
6, 10, 12
7, 12, 15, 16
8, 14, 18, 20
9, 16, 21, 24, 25
10, 18, 24, 28, 30
The products 1, 2, 3, 5, 7, 14, 15, 20, 21, 25, 28 and 30 can only be achieved in one way, and then matte would know what the numbers are. So these can be taken away. And since Besmira was sure that matte wouldn't know, the sums that belong to these products can be extracted.
Leaving us with:
5=4+1=3+2
7=6+1=5+2=4+3
with corresponding products:
4, 6
6, 10, 12
Since mattes states he knows what the numbers are now, it can't be 6, since it can be achieved in two ways, and then he wouldn't be sure which the numbers are. So it's not 3 + 2, or 6+1.
5 = 4 + 1
7 = 5 + 2, 4 + 3
are the ones left, and since besmira states she knows what the numbers when matte knows, the sum can't be 7, since it can be achieved in two ways.
Numbers must be 4 and 1.
Feel free to question or ask something.